Given 16.2 grams of substance Y, if the substance absorbs 2722 joules of energy and the specific heat of the substance is 9.22 J/g·°C, what is the final temperature of the substance if the initial was 26 degrees Celsius?
Select one:
a. 18.0°C
b. 44°C
c. 1550°C
d. 8°C

Question

Given 16.2 grams of substance Y, if the substance absorbs 2722 joules of energy and the specific heat of the substance is 9.22 J/g·°C, what is the final temperature of the substance if the initial was 26 degrees Celsius?
Select one:
a. 18.0°C
b. 44°C
c. 1550°C
d. 8°C

anonymous · Answer

$$Q=CM \Delta T$$
Where Q is equal to the heat added, measured in Joules. C is the specific heat. M is the mass. Delta T is the change in temperature. From there can you plug the numbers in for yourself?

anonymous · Answer

i have no idea how to do these equations

anonymous · Answer

Put the values in for what I told you.

anonymous · Answer

Thanks

anonymous · Answer

You're welcome.