Question

Help again please! :D

Evaluate the definite integral...

from 0 to pi 2sin(x) dx

Answer 1

you know the anti derivative of sine?

Answer 2

oh...is it not asking for the antiderivative of the antiderivative??? if i am saying that right lol

Answer 3

antiderivative of sine would be -cos right?

Answer 4

yes

Answer 5

your answer is therefore
\[-2\cos(\pi)+2\cos(0)\]

Answer 6

i am just confused to why the answer is just the antiderivative

Answer 7

and wouldn't you want to subtract the values from each other not add them? or is that from the derivative of the antiderivative?