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OpenStudy (anonymous):
Help again please! :D Evaluate the definite integral... from 0 to pi 2sin(x) dx
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OpenStudy (anonymous):
you know the anti derivative of sine?
OpenStudy (anonymous):
oh...is it not asking for the antiderivative of the antiderivative??? if i am saying that right lol
OpenStudy (anonymous):
antiderivative of sine would be -cos right?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
your answer is therefore \[-2\cos(\pi)+2\cos(0)\]
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OpenStudy (anonymous):
i am just confused to why the answer is just the antiderivative
OpenStudy (anonymous):
and wouldn't you want to subtract the values from each other not add them? or is that from the derivative of the antiderivative?
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