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Mathematics 20 Online
OpenStudy (anonymous):

SOMEONE PLEASE HELP (factoring)

jimthompson5910 (jim_thompson5910):

what do you need to factor?

OpenStudy (anonymous):

15q^3+40q^2+3q+8

OpenStudy (anonymous):

i dont understand factoring at all ive tried all day to learn but i couldnt understand the steps

jimthompson5910 (jim_thompson5910):

You have 4 terms, so let's try to factor this by grouping

jimthompson5910 (jim_thompson5910):

you start off by grouping up the terms into pairs 15q^3+40q^2+3q+8 (15q^3+40q^2)+(3q+8) what can you factor from (15q^3+40q^2) ?

hartnn (hartnn):

you know what factoring is, right ?

OpenStudy (anonymous):

isnt factoring basically grouping them? @hartnn

OpenStudy (anonymous):

i dont understand what you mean? so you factor each group alone? @jim_thompson5910

jimthompson5910 (jim_thompson5910):

ignore the variables for now let's focus on factoring single numbers what do you get when you factor 15 ?

OpenStudy (anonymous):

okay im sorry for sounding so stupid but what do you mean by " factor 15"

hartnn (hartnn):

its opposite to distributing \(\large ☻(☺+♥) = ☻☺+☻♥ \\ \text {this is distributing}\) \(\large ☻☺+☻♥= ☻(☺+♥) \\ \text{this is factoring, } \\ \text{☻ was common from both terms and factored out.}\) now is it clear, what factor basically means ?

OpenStudy (anonymous):

thats what someone on here was trying to explain that its distributing but in reverse

jimthompson5910 (jim_thompson5910):

factoring is writing a number as a product of 2 or more numbers

jimthompson5910 (jim_thompson5910):

for example, 10 = 2*5

OpenStudy (anonymous):

so 5 x 3

jimthompson5910 (jim_thompson5910):

good

jimthompson5910 (jim_thompson5910):

40 = 5*8, so we can see that 40 and 15 have a common factor of 5 this is the greatest common factor (the largest factor they share)

hartnn (hartnn):

one more example : \(abc+adc\) what is common from both terms? 'a' and 'c' , right ?? so i factor it out from the expression. in first term, 'b' remains and in 2nd term, 'd' remains so i will have \(ac (b+d)\) see if you get this. you will be applying this in your problem

OpenStudy (anonymous):

ohhhh that helped actually, thanks!! @hartnn and so we're finding the gcf, right? @jim_thompson5910

OpenStudy (anonymous):

what do we do with the exponents then? and the variables?

jimthompson5910 (jim_thompson5910):

exactly, so let's say we had something like 20x + 30y first we factor 20 and 30 20 = 2*10 = 2*2*5 30 = 3*10 = 3*2*5 we see that 2*5 or 10 is the GCF between 20 and 30 so we factor that out to go from 20x + 30y to 10(2x + 3y) notice how if you distributed the 10 back in you'd get 20x + 30y again

OpenStudy (anonymous):

ohhh that makes total sense now!

jimthompson5910 (jim_thompson5910):

Here's a way to visualize factoring 20x + 30y |dw:1398409758521:dw|

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