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OpenStudy (anonymous):
cosx(cosx-2)=1
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OpenStudy (aravindg):
Use distributive property.
OpenStudy (anonymous):
Sorry what? I'm doing lower sixth maths in England I don't know what that means?
OpenStudy (aravindg):
a(b+c)=ab+ac
OpenStudy (anonymous):
England?
OpenStudy (anonymous):
I know how to expand it, I don't know how to solve it...
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OpenStudy (aravindg):
First expand. Then you get a quadratic equation in cos x. Put t=cos x and solve for t.
OpenStudy (aravindg):
@meshlogic It's okay since you are new :)
OpenStudy (anonymous):
When I expand I end up with cos^2x - 2 cosx -1 = 0 How do I solve that it makes no sence
OpenStudy (aravindg):
Put t= cos x. You get a quadratic equation in t. Solve for t.
OpenStudy (anonymous):
I would then have t^2 - 2t -1 = 0 which cannot be factorised. (t - 1)(t + 1) doesn't expand to what I have...
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OpenStudy (anonymous):
Complete the square
OpenStudy (anonymous):
I'll try
OpenStudy (anonymous):
I now have -cosx = + or - 1
OpenStudy (anonymous):
Completing the square, did you get:
\[t^2-2+1 -1=0+1\\t^2-2+1=2\\(t-1)(t-1)=2\]
?
OpenStudy (anonymous):
oh I see where I went wrong, thank you :-)
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OpenStudy (aravindg):
Good work @meshlogic :)
OpenStudy (anonymous):
put the values for cos into a cast diagram and got the correct answer, thanks guys :-)
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