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Mathematics 25 Online
OpenStudy (anonymous):

cosx(cosx-2)=1

OpenStudy (aravindg):

Use distributive property.

OpenStudy (anonymous):

Sorry what? I'm doing lower sixth maths in England I don't know what that means?

OpenStudy (aravindg):

a(b+c)=ab+ac

OpenStudy (anonymous):

England?

OpenStudy (anonymous):

I know how to expand it, I don't know how to solve it...

OpenStudy (aravindg):

First expand. Then you get a quadratic equation in cos x. Put t=cos x and solve for t.

OpenStudy (aravindg):

@meshlogic It's okay since you are new :)

OpenStudy (anonymous):

When I expand I end up with cos^2x - 2 cosx -1 = 0 How do I solve that it makes no sence

OpenStudy (aravindg):

Put t= cos x. You get a quadratic equation in t. Solve for t.

OpenStudy (anonymous):

I would then have t^2 - 2t -1 = 0 which cannot be factorised. (t - 1)(t + 1) doesn't expand to what I have...

OpenStudy (anonymous):

Complete the square

OpenStudy (anonymous):

I'll try

OpenStudy (anonymous):

I now have -cosx = + or - 1

OpenStudy (anonymous):

Completing the square, did you get: \[t^2-2+1 -1=0+1\\t^2-2+1=2\\(t-1)(t-1)=2\] ?

OpenStudy (anonymous):

oh I see where I went wrong, thank you :-)

OpenStudy (aravindg):

Good work @meshlogic :)

OpenStudy (anonymous):

put the values for cos into a cast diagram and got the correct answer, thanks guys :-)

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