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Mathematics 20 Online
OpenStudy (anonymous):

Evaluate Functions PLEASE HELP

OpenStudy (anonymous):

OpenStudy (anonymous):

just sub in t=10 for the number of working days in 2 weeks

OpenStudy (anonymous):

it would be 31

OpenStudy (anonymous):

OpenStudy (mathmale):

@Starr_DynastyT : You could help the rest of us help you if you'd show how you obtained your answer. It'd take just a few moments to type out your work. I'd like to understand your reasoning.

OpenStudy (anonymous):

After two weeks on the job a new employee should be assembling 31 complete pads per day.

OpenStudy (anonymous):

i used learning curve function for the number of pads assembled per day to determine a new employee's output for two weeks on the job, which is ten work days.

OpenStudy (anonymous):

These questions just require you to sub in values. That's all-- piece of cake.

OpenStudy (mathmale):

I agree: t=10 days. What are you looking for? Have you any doubt about your answer being correct?

OpenStudy (anonymous):

\[P(10)=47(1 - e^-0.11(10) ) \]

OpenStudy (mathmale):

Let's break the calculations down: Assuming that t=10 days, calculate -0.11(10).

OpenStudy (anonymous):

\[=47(1-e^-1.1)\]

OpenStudy (mathmale):

All right...now please evaluate e^(-1.10.

OpenStudy (anonymous):

\[=31.35505906619\] After two weeks on the job a new employee should be assembling 31 complete pads per day.

OpenStudy (mathmale):

OK. You're jumping ahead of what I was asking y ou to do. But your result appears to be very reasonable. Note that as time goes on, the exponential function part of your formula decreases, so that eventually the worker will reach a production of 47 per day, right?

OpenStudy (anonymous):

correct

OpenStudy (mathmale):

Hope you are comfortable with this solution. Any questions?

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