The equilibrium system N2O4(g) 2NO2(g) was established in a 1.00-liter vessel. Upon analysis, the following information was found: [NO2] = 0.500 M; [N2O4] = 0.0250 M. What is the value of Keq?

20.
0.050
10.0
0.10

Question

The equilibrium system N2O4(g) 2NO2(g) was established in a 1.00-liter vessel. Upon analysis, the following information was found: [NO2] = 0.500 M; [N2O4] = 0.0250 M. What is the value of Keq?

20.
0.050
10.0
0.10

anonymous · Answer

no one?

aaronq · Answer

Do you know how to write equilibrium expressions?

aaronq · Answer

Like this:

 aA + bB $\rightleftharpoons$ cC + dD 

$K_{fwd}=\dfrac{[C]^c*[D]^d}{[A]^a*[B]^b}$

anonymous · Answer

no, and i got that one wrong :(

anonymous · Answer

that looks like it makes sense though

aaronq · Answer

okay, it's pretty easy the main focus is to arrange them like this:

$K=\dfrac{[products]}{[reactants]}$

then you assign exponents according to the stoichiometric coefficients. Give it a try

anonymous · Answer

Okay so, that makes a lot more sense... so would i then just solve the equation for my question above?

aaronq · Answer

yeah, don't forget the exponent though.

anonymous · Answer

is it .10?

aaronq · Answer

hm thats not what i got.

$\dfrac{0.5^2}{0.025}=10$

anonymous · Answer

okay, yeah. thanks man.

aaronq · Answer

no problem, dude