Question

1/sin^2 - 1/tan^2 = 1

Answer 1

What are you trying to do?

Answer 2

Its the things where you have to use the identities.

Answer 3

Ok. You want to prove the identity.

Answer 4

Multiply both sides by sin^2 theta

Answer 5

\(\dfrac{1}{\sin^2 \theta} - \dfrac{1}{\tan^2 \theta} = 1\)

\(\dfrac{1}{\sin^2 \theta} \times \sin^2 \theta - \dfrac{1}{\tan^2 \theta} \times \sin^2 \theta= 1 \times \sin^2 \theta\)

Now use the identity \(\tan \theta = \dfrac{\sin \theta}{\cos \theta} \) on the left side to deal with \(\tan^2 \theta \).