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this makes no sense. help please? If cos Θ = -2/5 and tan Θ > 0, what is the value of sin Θ?
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\[\sin (\theta )=\sin \left(\cos ^{-1}\left(-\frac{2}{5}\right)\right) \]
\[\sin (\theta )=\frac{\sqrt{21}}{5} \]
i got a syntax error on my calculator. im still confused @robtobey
if cosine is negative, which quadrant do you think theta is in?
negative square root 21 negative square root 21 / 5 square root 21 / 5 square root 21 / 2 @sourwing @robtobey
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yes, which quadrant theta is in if cosine is negative?
sin x = -(V21)/5 since tan x > 0. See drawing.
It isn't square root 21/5
@thu1935 so it's negative square root 21 / 5?
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