Question

What is the amplitude, period, and phase shift of f(x) = −4 sin(2x + π) − 5?

Answer 1

Compare your
f(x) = −4 sin(2x + π) − 5 to:
y = a*sin (bx + c) + d

Your a value is -4; your b is ?
your c is ?
your d is ?

the amplitude of your sine wave is |a|, the absolute value of a.
The period is 2Pi/b
what is the horizonal phase shift?
What is the vertical offset?

Answer 2

use this y=Asin(Bx-C),A=amplitude, Period=2pi/B, Phase shift=C/B

Answer 3

thanks but mathmale deserves the medal :)

Answer 4

so amplitude is -4, Period is pi
im confused on phase shift
@sidsiddhartha @mathmale

Answer 5

is phase shift pi/2

Answer 6

yes i think so

Answer 7

Actually, the phase shift is -c/b. But you're close!

Answer 8

There's also a vertical offset. Your value of d is -5. that means you graph the sine function first, and then, when you're done, you shift the whole graph downward 5 units.

Answer 9

So is the phase shift -pi/2 @mathmale

Answer 10

@mathmale ^^^^

Answer 11

that's right! you draw the basic sine function. Then, whn you've finished, you shift the WHOLE GRAPH pI/2 units to the left. Then, as before, you shift the whole graph downward by 5 units. then you're done!

Answer 12

Which answer do you believe is correct, based upon our discussion?

Answer 13

@mathmale would it be A?

Answer 14

sorry, no, primarily because the amplitude is positive 4, not negative 4. Your a is neg, but the ampl. is |a| = |-4|=?

Answer 15

enjoyed working with you!! but I need to get off OpenStudy and the 'Net and get some work done. See you again!

Answer 16

@mathmale so it's C, then.
thank you for your help. (:

Answer 17

Ty so much! This was correct (just took it)