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\[\int\limits\limits \frac{ \sqrt{9-x^2} }{ x^2 }dx \]
convert x to something 3 sin?
to attain 1 - sin^2 = cos^2
Dang. I'm not good at trig subs. Does this have to do with inverse trig functions?
take x=3sinz
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how would you do it without trig sub? using long methods with regular integration?
that is what I thought @sidsiddhartha gautama buddha thanks
do it :):)
\[\int\limits \frac{ \cos^2 \theta }{ \sin^2 \theta }d \theta\]
thank you once again
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yes that' s it
mention not :p
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