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Given A =1/2(b1 + b2)h, solve for h?
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I know that you have to isolate h.
okay good now remember PEMDAS?
yes sort of but would i distribute 1/2?
yes, because you have to take away the P in PEMDAS first which is parentesis.
ok so where would "A" go. Would you have to subtract it by 1/2
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its easier to show you then explain..will you let me?
sure please do
okay. A =1/2(b1 + b2)h A =(b1 + b2)h (2) 2*A= (b1+b2)h 2*A= (b1+b2)h /(b1+b2) \[2A \div (b1+b2)= h\]
does that help?
ok so wait how did you get this again: A =(b1 + b2)h (2). did you distribute?
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I times two on both sides to get rid of 1/2
to get 2A
oh ok got it. I understand now thanks! :)
Welcome! I hope that helped! ^^
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