Question

Question below:

Answer 1

consider every option. let's look at A, what is it saying?

Answer 2

The function of A intersection B is same as f(A) intersection f(B)

Answer 3

consider that logically
let's consider A = {1, 2, 3} and B = {2, 3, 4} and f to be a scaling mapping with a scale of 5, e.g. f(A) = {5, 10, 15} (i don't feel like using latex so saying scale mapping is good enough)
is f(a int b) = f(a) int f(b)

Answer 4

f A int B=4,6
f(A)=1,4,6
f(b)4,6,8
f(a) int (b)=4,6

Both are equal?

Answer 5

@ganeshie8 How to approach this other than taking examples?

Answer 6

ive no clue sorry :(

Answer 7

@experimentX is here :)

Answer 8

thinking at the moment ... rather think about contradiction than proving it.

Answer 9

C) is definitely wrong

Answer 10

Yeah hope he can come up with a good solution :). This is for an objective test that I will take on Sunday. So during exam I can't waste much time taking examples for each option.

Answer 11

D) is wrong too ...

Answer 12

Can you tell me how you are arriving at these conclusions?

Answer 13

if \( A \cap B \neq \{\phi \}\), definitely \( f(A\setminus B) < f(A)\)

Answer 14

choice C) is simply stupid ... between A) and B) i have to choose one now.

Answer 15

f(A\B) is read as f(A) given B right?

Answer 16

No ... A\B = A - B

Answer 17

Oh I didnt know abt that notation.

Answer 18

are more than one option right?

Answer 19

Only 1 option is right.

Answer 20

i would wager my money on first lol

Answer 21

haha

Answer 22

trying to find something wrong with 2

Answer 23

Anyways now I have a faint idea on how to approach such problems. Thanks!!

Answer 24

have it's solution??

Answer 25

No :(

Answer 26

@AravindG You're doing amazing :D

Answer 27

lol thanks :D

Answer 28

my brain exploded

Answer 29

You're welcome @AravindG