Converge to what? ( 1 + ( 1/n ) )^2n
I know the answer is e^2.. but I was hoping someone can show how. I tried the ratio test, but got it wrong!
\[e^{ \lim_{x \rightarrow \infty}( 1 + ( 1/n ) )^2n } \]
sorry the n is an exponent as well
Hello, thanks for answering! Why is it that we raise the exponent here with e?
than you drop the 2 so it becomes e^2(the limit)
usually when we have exponents and we don't know how to solve the type of equation using a method we already know, we resort to using e to drop the exponent
What technique is that? Haven't come across it yet in my studies
the limit changed to 2n log (1+1/n) btw
I learnt it in highschool calculus, i dont remember which section exactly though
okay i'll do some researching then. Thanks! problem solved
your welcome :)
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