Question

Please verify, find the x intercept of the function f(x)=2 ln(x-3)
0=2(lnx-3)
0=lnx-3
3=lnx 3= loge^x
X= e^'3

Answer 1

0=2(lnx-3) OK
0=lnx-3 Should keep those parentheses! 0=ln(x-3)
3=lnx 3= loge^x There is no advantage to re-writing 3=ln x. 3=ln x is correct as is.
X= e^'3 Mind explaining how you got this result? Please delete the ( ' )

Answer 2

I replaced x with 3 to get e^3 or should it be -3

Answer 3

(In answer to your question: No.)
If 3=lnx: Treat both sides of this equation as exponents.

Write the simple equation e = e
Use that 3 as the exponent for the first e and that ln x as the exponent for the second e.
Write this out, please.

Answer 4

e^3 = e^3? I'm not sure what you want me to do. Or is the answer ln^ 3 = loge^3
X inltercept loge^3

Answer 5

\[\ln(x - 3) =0\]\[\log_{e}{(x-3)} =0\]\[e^0 = x - 3\]

Answer 6

Note that \(\ln(x - 3)\) should NOT be written as \(\ln(x) - 3\).

Answer 7

Oh, just noticed that mathmale had already pointed that out. Sorry.

Answer 8

@parthkohli: Here's your medal for noticing what I had not noticed!

@Nancyo: Sorry. Looks like it's back to the drawing board. We'll need to start over. Solve for x, if 0=2ln(x-3).

Answer 9

Think: ln 1 = 0. Can you use this fact to solve 0=2ln(x-3)?

Answer 10

I may be way off base
Ln 1 =0 bc e^0 =1
Ln e =1 bc e^1 =e

So now I have:
0= 2ln(lnx-3)
0= ln(x-3)
Loge(x-3)=0
e= x-3. 1=x-3
X=4?

Answer 11

ln 1 = 0. Can you use this fact to solve 0=2ln(x-3)?

Here's how: We know that ln 1 = 0.
Therefore, if ln(x-3) = 0, x-3 must be 1.
So your x=4 is correct.

any questions regarding this particular math problem?

Answer 12

I think I understand now, thank you very much for the help!