Question

given triangle ABC whose sides are AB=15in., AC=25in., and BC=30in., . from a point D on side AB, a line DE is drawn to a point E on side AC such that angle ADE is equal to angle ABC. if the perimeter of triangle ADE is 28m. .find the lengths of line segments BD and CE

Answer 1

sounds like similar triangles to me

Answer 2

as such, the perimeter of one is just a scaled version of the other

Answer 3

i can sketch it :(

Answer 4

draw a triangle with a line parallel to the stated side

Answer 5

we are the same

Answer 6

good, as such we are looking to find a scalar value to find AD and AE to finish the solution

Answer 7

the ADE is form a scalene triangle

Answer 8

the scaled parts are such that for some value k:

15k + 25k +30k = 28 ... is that meters? if so we would want to convert it to inches so be in the same dimension as the stated side values

Answer 9

check to make sure thats spose to be 28m, and not 28in otherwise check the stated side values and see if their units values are correct

Answer 10

yes sir thats inches

Answer 11

so 28 inches is a better situation to play with ... no conversions needed :)

so lets solve for k

Answer 12

15k + 25k +30k = 28

k(15 + 25 +30) = 28

k(70) = 28 .... whats the value for k?

Answer 13

2/5

Answer 14

2/5 i like ... soo now the question is reduced to:

BA = BD + AD, but AD = BAk

BA = BD + BAk

BA - BAk= BD, is one answer, same concept applies to the other side

Answer 15

9 and 15???

Answer 16

9 is good:

15-15*2/5 = 15-6 = 9

25-25*2/5 = 25-10 = 15, i like it

Answer 17

i got it sir thank you :)

Answer 18

youre welcome, and good luck :)

Answer 19

your the best :)