Question

integral 1 to 2 ((x^2-x)/(x^3))

Answer 1

Let me rewrite it so it can be read easily:
\[\large \int\limits_{1}^{2} \dfrac{x^2-x}{x^3}dx\]

Answer 2

ah ok, you can split the function like this: \[\large \int_1^2 \dfrac{x^2}{x^3} - \dfrac{x}{x^3} dx = \int_1^2 \dfrac{1}{x} - \dfrac{1}{x^2} dx \\ \large = \int_1^2 \dfrac{1}{x}dx - \int_1^2 \dfrac{1}{x^2} dx\]

Answer 3

Does that help you?

Answer 4

yes thank you

Answer 5

does the 1/x become ln?

Answer 6

yes

Answer 7

can you help me with another integral question plz?

Answer 8

Sure