You deposit $5000 into an account that earns 5% compounded annually. A friend deposits $4750 into an account that earns 4.95% annual interest, compounded continuously. Will your friend's balance ever equal yours?
I tried making the equations for this: yours:\[A=5000(1+.05)^t\] friends: \[q=4750*e ^{0.0495*t}\]
and graphed them to see when they would intersect but found they didn't but my homework says that's wrong. Not sure where to go with this now
@ganeshie8 are you able to help with this one?
see if \(e^{0.0495} \gt 1+0.05\) is true
if it is, then the `continuous compounding` curve grows at a greater rate and overtakes the `annual compounding` curve at some point for sure
well unless my equations are wrong they ran pretty consistently alongside each other when I graphed it
graphing is a good idea, but consider the possibility that they might cross much far away... half way before infinity ?
if the `continuous` growth rate is even a hair greater than the `annual compounding` growth rate, then the `continuous` wins in the long run
not with the curves they were at. they would have to curve back around towards each other which isn't a quality of exponential equations. so I did something wrong somewher
Did u check if below is true : \(e^{0.0495} \gt 1+0.05\) ?
yeah, it's > by like o.ooo7
lol thats more than a hair
so ur friend's balance is growing at a slightly greater rate than your balance
so he will over take u after few years
you may not be living to see it though... he reaches it in approximately 72 years : http://www.wolframalpha.com/input/?i=solve+5000%281%2B.05%29%5Et+%3D+4750*e+%5E%7B0.0495*t%7D
so is 72 years when our accounts will be equal? I'm confused
yup thats what wolfram says
but u dont need to work that
the question is asking u only whether he will ever reach ur balance or not
for that checking the growth rate is sufficient
no the question is asking WHEN he will equal mine
you better read the question again :/
or i must have overlooked something, let me go thru again lol
that's what the question says but the answer box says " ____years (if he never reaches your balance enter NEVER)"
72 was right. i just have no idea how you got it
can you just show me how you got 72?
ohhk.. cool :)
you wanto knw when the balances in both accounts equal, so simply equate both the equations and solve for \(t\)
you equation : \(A=5000(1+.05)^t \) your friend's equation : \(q=4750*e ^{0.0495*t}\)
set them equal : \(5000(1+.05)^t=4750*e ^{0.0495*t}\)
solve
oh okay, that makes more sense, thank you :D
np :)
wait, one more question. How would you go about solving that? Would you take the log of both sides? your link to wolfram was kinda confusing on how to solve it. I have to show my work or I don't get credit
\(5000(1+.05)^t=4750*e ^{0.0495*t}\) divide 4750 both sides : \(\dfrac{5000}{4750}(1.05)^t=e ^{0.0495*t}\) divide (1.05)^t both sides : \(\dfrac{5000}{4750}= \dfrac{e ^{0.0495*t}}{(1.05)^t}\) which is same as : \(\dfrac{5000}{4750}= \left(\dfrac{e ^{0.0495}}{1.05}\right)^t\)
Now you can take log both sides and isolate \(t\)
Okay, i got it now.
Thank you :)
u wlc :)
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