Question

The product of two consecutive even integers is 10 less than 5 times their sum. Find the two integers.

Answer 1

write the equation and then solve it.
i did it in my head so it's not too hard... the question, that is. my head is pretty hard.

Answer 2

lol How do I write the equation?

Answer 3

8+10=18, 18*5= 90
8*10=80

Answer 4

let x and x+2 be the two consecutive integers.

then x(x+2)+10=5(x+(x+2))

Answer 5

That looks sooo confusing lol

Answer 6

\(x^2+2x+10=10x+10\)
solve for x.
you should get two answers...

Answer 7

8 & 10

Answer 8

nope, that's only one set of answers... there's another

Answer 9

My online work says I need 2 different sets of numbers, lower & higher values

Answer 10

ooooh, uhh...I don't know lol

Answer 11

Do I replace 8 & 10 with x or no?

Answer 12

well, learn.

it's pretty easy if you just give it a shot.

Answer 13

get the x's on one side of the equation. it simplifies and then factor. set each factor equal to 0 and solve for x.

you can do it!

Answer 14

Do I combine like terms? like 2x & 10x & both 10s?

Answer 15

subtract 10x and 10 from both sides... what do you get?

Answer 16

x^2-8x?

Answer 17

=?

Answer 18

x^2-8x=0

Answer 19

yep, now factor the left hand side

Answer 20

4 & 2? I don't know which is negative.

Answer 21

\(x^2-8x=0\) what is common to both terms on the left?

Answer 22

x
x(x-8)?

Answer 23

there you go. now set each factor equal to 0 and solve for x

Answer 24

x=0 & x-8=0?

Answer 25

yep

Answer 26

so, it's 0 & 8?

Answer 27

yep

Answer 28

my online work says 8 is wrong :/

Answer 29

remember. x and x+2 are the two consecutive even integers. as orangemaster pointed out, 8 and 10 are one set of consecutive even integers

0 and 2 are the others

Answer 30

ooooooh, that's why lol

Answer 31

good luck!

Answer 32

Thank you! Can you help me with the next one too?