Question

Reduce the following rational expression to lowest terms, if possible.
(Problem in comments...)
@ganeshie8

Answer 1

\[\frac{ y+4 }{ y^2-16 }\]

Answer 2

Hi ! @hartnn *waves* ^_^

Answer 3

hello :)

Answer 4

You two are thee best ! lol

Answer 5

I'll give one hint : \(a^2 - b^2 = (a+b)(a-b)\)

Answer 6

lol that motivates me for giving one more hint : \(16 = 4^2\)

Answer 7

wouldnt the two y+4s cancel out?
So ill just have y-4

Answer 8

You got it ! piece of cookie for u :)

Answer 9

in the denominator, yes!

Answer 10

lol, thank you...these are kinda easy...well so far lol dont go too far, you two! next question!

Answer 11

Jeeze @hartnn and @ganeshie8 you guys are turning people into pros within 5 minutes. Teach me the ways!

Answer 12

They are geniuses lol

Answer 13

too many kind words today lol xD ty :)

Answer 14

wait, wait, wait! not done with the question !!
Specify the restrictions on the variable. (Select all that apply.)
y ≠ 16
y ≠ -4
y ≠ -16
y ≠ 4
y ≠ 0

Answer 15

you do knw that denominator can never become 0 right ?

Answer 16

Yes, someone told me that

Answer 17

\(\dfrac{ y+4 }{ y^2-16 } = \dfrac{ y+4 }{ (y+4)(y-4) } = \dfrac{1 }{ y-4 } \)

Answer 18

to figure out the restrictions, look at ur `original` rational expression

Answer 19

\(\dfrac{ y+4 }{ y^2-16 } \)

Answer 20

you said, denominator cannot equal 0,
so tell me what makes the denominator become 0 ?

Answer 21

those will be the restrictions

Answer 22

to find out the restrictions, you can simply set the denominator equal to 0 and solve :

\(y^2 -16 = 0\)

\(y = ?\)

Answer 23

Tempted

Answer 24

16? maybe 4 lol

Answer 25

\(y^2 -16 = 0 \\ y^2 = 16 \\ y = ?\)