Question

Reduce the following rational expression to lowest terms, if possible.
(Problem in comments)

Answer 1

\[\frac{ 6a^3-13a^2+7a }{ 2a^3-5a+3a }\]

Answer 2

this doesnt look solvable lol

Answer 3

2 numbers with sum = -13 and product = 6*7 =42
are ?

Answer 4

6 & 7?

Answer 5

both negative :)
-6, -7

Answer 6

and -2 + -3 =5

Answer 7

-5

Answer 8

correct!

Answer 9

so how do we solve this? lol

Answer 10

factor the numerator
\(a (6a^2-6a-7a+7) \\ a(...?...)\)

Answer 11

a(6a-6-7...how would i factor the last 7, it doesn't have an a...

Answer 12

factor 'a' only from first 2 terms
factor -7 from last 2 terms

Answer 13

factor 6a** from first 2 terms

Answer 14

ooooh ok

Answer 15

\(\large a(6a(a-1)-7(a-1))\)
got that ?

Answer 16

yes

Answer 17

factor out a-1 now

Answer 18

\(\large a(6a(a-1)-7(a-1)) \\ \large a(a-1)(6a-7)\)

got that ^

can you do the same thing for denominator?

Answer 19

ill try lol

Answer 20

a(2a^2-2a-3a+3)?

Answer 21

a(2(a-1)-3(a-1))

Answer 22

@ganeshie8