Question

pythagorean identity to find sin t
cos t = -1/2 and pi 12 years ago

Answer 1

s^2 + c^2 = 1 ... solve for s

Answer 2

keep in mind the quadrant its asking for, as that tells us whether or not sin is positive or negative

Answer 3

well I did
sint^2=1+(1/2)^2
sin t = 1+1/4
sin t = -sqrt 5/2
but it's the wrong answer =/

Answer 4

of course its wrong ..

s^2 + c^2 = 1
- c^2 - c^2
----------------
s^2 = 1-c^2 ; not 1+c^2

Answer 5

cost is a negative, negative and negative is a positive..

Answer 6

doesnt matter ....

Answer 7

well if subtracting cost wouldn't it be 1- (-1/2)^2 ?

Answer 8

s^2 + (-1/2)^2 = 1

s^2 + 1/4 = 1
- 1/4 - 1/4
-----------------
s^2 = 1 - 1/4

Answer 9

oh um.... hold on let see....

Answer 10

Oh I see, thanks! I see my mistake, can you help me with just 1 more same concept got the wrong answer but idk why.

Answer 11

sure

Answer 12

cost = 1/2 and 0<t<pi/2 I got sqrt 1/2 but um its wrong =/

Answer 13

quad 1, so cos and sin are + ..

cos is still 1/2 .... so sin is still gonna be 1-(1/2)^2 is still gonna be sqrt(3)/2 but in quad 1 all is positive

Answer 14

in other words, you didnt square the c in this case

Answer 15

Ohh wow i forgot, thanks for clarifying!! I see my mistake now!

Answer 16

the hardest part in math is not learning new concepts, its holding on to the stuff we already learned lol

Answer 17

Lol I know i easily get confused at wrong answers lol.

Answer 18

good lcuk ;)

Answer 19

are you a math major in colelge ?

Answer 20

luck even ....

Answer 21

just graduating with a BA in math ...

Answer 22

Oh wow what college ?

Answer 23

saint leo university ... it was the closest place to where i live.

Answer 24

Oh nice, well thanks again for your help, im so stressing for my finals next week lol got a lot to cover.

Answer 25

youre welcome, and relax, youll do fine

Answer 26

aw thanks lol.