Plz help!!! I have a midterm on monday and have no idea how to solve this. I need help solving R2 and R3. We have to use only the concepts of circuits and can only use the formulas: V=IR and P=IV
have to see how the circuit is arranged. do you have a pic?
oh sorry ya i thought i put the picture. just a sec
if you cant see anything, just tell me and ill just write out the numbers
ok, so we need VIRP table, right?
i guess
oh, Vincent is here, let him help. Please @Vincent-Lyon.Fr
ok
for R2, you mark I =34A and V =40V , right?
no just 40 V the 34A goes through the whole section since it has to be divided among the other resistors.
right?
Please, post original picture with original given data. Don't put your stuff there.
R2 = 40V / 34A = 1.18Ω etc.
Totally different!!! they ask you to calculate equivalent R between R2 and R3, right?
and where is R6? do you mix 2 problems ? hahahaha
no. i just have to figure out the current and volts for each resistor and the battery with the given info. i had already figure everything out for all the resistors except R2 and R3
that was for the next problem. sorry. ok here is the data for this problem
sorry for the bad quality, im taking these with my ipod
wait @loser66 where did you go? i still need help
hey @Vincent-Lyon.Fr why did you divide 40V by 34A
this is a parallel circuit right? the current has to distributed amongst the resistors so all the current cant go to one resistor right?
R = V/I for a resistor.
yes but not all the 34A goes to R2 since it has to go to R3 as well right?
No, according to your picture 34 amps go through R2.
then how much goes through R3?
24? since 10 A would go to R4 and R5?
plz help i have a midterm on monday!
if you dont know how to solve it just say it so i can ask others
dont just leave. thats not nice. thx for staying loser66
I am trying, but not have the answer yet. I need it, too. hihihi
kk thx so much. i have the answers if you want but dont know how to solve it.
ok, just post. I need it, too.
kk. hold on.
Thanks for posting, let me try to find the logic on it.
no problem. the wierd thing is i have already solved it before with the right answers, but now i dont remembber how i did it. :( its so frustrating!!!1
Since Vbat = 60 V, then V1 = 60 V too because they are in parallel. So I1 = 60/10 = 6A So I2 = 40 - 6 = 34A Since V3 = 20V, then V2 = V1 - V3 = 60 - 20 = 40 V So R2 = 40/34 = 1.17 ohm etc. use additivity of currents at nodes and additivity of potential differences in series. I must go.
ok thx.
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