Find all polar coordinates of point P where P =(5,pi/3)
@iPwnBunnies
(5, pi divided by 3 + nπ) or (-5, pi divided by 3 + nπ) (5, pi divided by 3 + (2n + 1)π) or (-5, pi divided by 3 + 2nπ) (5, pi divided by 3 + 2nπ) or (-5, pi divided by 3 + (2n + 1)π) (5, pi divided by 3 + 2nπ) or (-5, pi divided by 3 + 2nπ)
Ok. It looks kinda confusing. Do you understand that 2pi radians makes a complete circle. And pi radians a half a circle?
yep i understand that
Ok. So if we have point (5, pi/3) If we add any multiple of 2pi to the pi/3, it'll just go back to the same angle, right?
yah makes sense
Good, so for the first part, we can write it like this: \[(5, \frac{\pi}{3} + 2 \pi n)\] Where 'n' can be any integer.
Alright, ya that eliminates 2 options :D
Yes! Now, for the next part.
(5, pi/3) is the same as (-5, pi/3 + pi)
It's the angle exactly opposite of pi/3. But since 'r' is negative, we trace it backwards, so it's the same point.
hmmm alright. ya i understand that
Ok, good. However, it can't be any multiple of pi. Because if we use pi/3 + 2pi, that'll be an angle similar to pi/3, which isn't what we want. We want every ODD integer, which we can write like this: \[(5, \frac{\pi}{3}) = (-5,\frac{\pi}{3} + (2n + 1)\pi)\] Where 'n' is any integer.
Thanks man! Do you have time for one more problem? It's my last one. I really appreciate your help
Ok.
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