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3+10+17+24+...+7003+7010, How do I find the "n' for the formula Sn = n/2 (a1+an)?
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well I'd use the equation for a term in an arithmetic sequence rather than the sum equation. you know the nth term is 7010 and the 1st term is 3 as well as the common difference is 7 so substitute them into \[a_{n}= a_{1} + (n - 1) \times d\] which becomes \[7010 = 3 + (n - 1) \times 7\] now solve for n
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