Power Series
Given f(x) Find...
My trouble is, what happen to the "-1". I have tried working it out and i don't know how they got rid of it?
take the absolute value, that's how they get rid of it
they replaces each \(x\) by \(2x\) they divide every term by \(x\) then they changed the sign of every term
@satellite73 yes but what happen to the "-1" ? :|
oh i am an idiot they subtracted 1!
that isn't "times \(-1\) that is just -1
@satellite73 ohhh so its just ONE "-1" and that is why the "1" at the beginning went away?
\[1-\frac{x}{8}+\text{blah blah blah}-1=\frac{x}{8}+\text{blah blah blah}\]
yes, that advanced arithmetic where \(1-1=0\) lol i fell for it too...
@satellite73 ah! i get it. what i was doing was putting "-1" after ever "2x" i substituted
So it left me with a lot of "-1" 's
good!
oops
actually this is a good problem for that reason like asking if \[\sum_{n=0}^{\infty}\frac{1}{2^n}=2\] then what is \[\sum_{n=1}^{\infty}\frac{1}{n^n}\]
typo but you get the idea arithmetic still works in power series so does multiplication, division etc
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