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Find the polynomial f(x) that has the roots of -2, 3 of multiplicity 2.Explain how you would verify the zeros of f(x)
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The polynomial has the multiplicity 2 right? Or is it the roots that have the multiplicity?
The polynomial has the multiplicity 2
Ok then you know that since the multiplicity is 2, the maximum amount of real roots is 2.
So yo can just do f(x) = (x+2)(x-3)
To find the roots of an equation, you set f(x) = 0 and solve. So when we check it, it is 0 = (x+2)(x-3). x=-2 and x=3 will be your roots
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Does this make sense?
Yes It Do.
ok cool. Tell me if you need more clarification
Okay.Thank You So MUCH
Can u help me with another one please
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