Question

solve by completing the square.
x2^2-4x-1=0

Answer 1

is it supposed to be 2x^(2)-4x-1=0 ?

Answer 2

@sierra1003 ? yes or no ?

Answer 3

yes

Answer 4

I sorry for the late respond I have a ton of homework and little time to do it.

Answer 5

you are trying to make the left side \[x^2+2x+1~~~~b/c~~i t's~~perfect~~squ are\]

Answer 6

add 3 to both sides
\[ 2x^2-4x-1=0\]\[ 2x^2-4x-1+3=0+3\]\[ 2x^2-4x+2=3\]\[2(x^2+2x+1)=3\]\[x^2+2x+1=3/2\]\[(x+1)^2=3/2\]

Answer 7

\[(x+1)^2= \frac{3}{2}\]\[x+1=±\sqrt{ \frac{3}{2} }\]\[x+1=± \frac{ \sqrt{3 } }{ \sqrt{2 } } \]\[x+1=± \frac{ \sqrt{6 } }{ 2 } \]\[x=-1± \frac{ \sqrt{6 } }{ 2 } \]\[x=-\frac{2}{2}± \frac{ \sqrt{6 } }{ 2 } \]\[x= \frac{ -2±\sqrt{6 } }{ 2 } \]see what I am doing ?