If f(x)= 2^x undergoes a transformation and becomes g(x)= -6f(x+1)-5 how would I graph that in a calculator? I forgot what to do with the f :/.

Question

anonymous · Answer

If f(x) is 2^x
then in the second we have f(x+1), so you plug (x-1) in for x in f(x), I think.
f(x-1) = 2^(x-1)

anonymous · Answer

Sorry, it's +1

anonymous · Answer

^^

anonymous · Answer

Wait so what would -6f(x+1)+5 be written as on a graphing calculator?

anonymous · Answer

Well we're inputting the function f(x+1)
so we'd have
g(x)=-6f(x+1)+5
     =-6(2^(x+1))+5

anonymous · Answer

If there aren't any brackets or anything missing, that's what we'd input.

anonymous · Answer

ohhh I get it, thanks! :)