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OpenStudy (anonymous):
Two friends, Bob and Ben, each buy one lottery ticket. Each ticket contains six numbers from a total of one hundred numbers (0–99). Bob chooses the numbers 1, 2, 3, 4, 5, 6, and Ben chooses the numbers 39, 45, 66, 72, 74, 89. Who has a higher probability of winning? A-Ben B-Bob C-both have an equal chance D-insufficient information
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OpenStudy (kropot72):
We can assume that there is one winning number. Each number on a ticket represents a random selection of a number from 0 to 99. Therefore each number has a probability of 1/100 of being the winning number. Six different numbers have a 6/100 probability of containing the winning number. Can you see the correct choice now?
OpenStudy (anonymous):
No 😭
OpenStudy (anonymous):
they are equal chances
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