MEDALS AWARDED eliminate the parameter. x = square root of t y = 2t + 5
\[x=\sqrt{ty}\] Square it and solve for t
Okay but I need a y = equation @AravindG
Once you can get t substitute in the equation.
Options: a. y = 2 sqrt x+ 5, x ≥ 0 b. y = 2 sqrt x - 5, x ≥ 0 c. y = 2x2 + 5 d. y = 2x2 - 5
How do I find t?
@hartnn
x = sqrt t square both sides u will get t now plug this t in your y= ... equation
@hartnn x = square root of t y
not actually its the way she has written, its confusing actually x= sqrt t and y=2t+5
oh ..Please use eqn editor next time
looking at tue choices, I m pretty sure about that
Sorry. But yeah, @hartnn is right about how it's written.
did u get t in terms of x?
Ha okay, wait. The answer is c (y = 2x2 + 5 ). Right?
yes:)
Thank you :)
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