The effusion rate of an unknown gas is measured and found to be 31.50 mL/min. Under identical experimental conditions, the effusion rate of O2 is found to be 30.50 mL/min. If the choices are CH4, CO, NO, CO2, and NO2, what is the identity of the unknown gas?
@iPwnBunnies @parna @primeralph
its kinetic molecular theory
@RatzLover95
Use Graham's Law of Effusion.
BUT HOW i never used this law
\[\frac{rate_a}{rate_b} = \sqrt{\frac{M_b}{M_a}}\]
im confused ?
The ratio of the two rates of two gases is equal to the square root of molar masses of the two gases, but flipped
i stil dont get it
We know the rate of effusion for the O2 and the unknown gas. We know the molar mass of O2 from the Periodic Table. We just need to find M of the unknown gas.
wait so 30.50 ml is ma?
No, that is the rate of one of the O2.
Let A be the O2, and B be the unknown gas. We're trying to find Mb.
ok and wats ma?
Ma is the molar mass of O2.
31.50ml/min is ma?
No..That's the rate of the unknown gas, B.
Let's solve for Mb first, that's what we're trying to find so we can identify the unknown gas.
is this right so far 30.50ml/min/31.50ml/min?
Yeah, that'll be the left side. Next step to isolate Mb?
how do you find ma though?
We can find Ma from the Periodic Table. O2 has two moles of oxygen in it. From the Periodic Table, we can see O has a molar mass of 16 g/mol. So, O2 has a molar mass of 32 g/mol
oh ok so its 30.50ml/min/31.50ml/min=square root of mb/32g/mol?
Yes.
ok so the left anwser is .96ml/min?
Sure, I trust you can do that lol.
is it right?
Just that part? Idk...I'm pretty sure it should be that. Now, next step in solving for Mb?
so for the square root dont you multiply by ^2 to cancel the square root symbol?
That's not multiplying. But you do square both sides to get rid of that square root.
oh i meant square sorry
so is the left 0.96ml/min^2?
Well, yeah. But you have to square the number for it to be useful. :3
so i square 32 as well?
Plus, there are no units, since when you divided those two rates, the units cancelled out.
@RatzLover95
No, when you square the right side, you just get rid of the square root there. The numbers don't change.
oh ok then wat?
then do u multpily 32 nd .96?
Well, what number did you get on the left side? You had to square 0.96.
yes?
o.o Square 0.96, since we squared both sides.
so u multpily square .96 and 32?
Err, ok, yeah, we can keep the square there for now. Yes, now you'll have to multiply by 32 to get Mb by itself.
kay well i got 30.72?
You didn't square the 0.96 like I told you to.
(0.96)^2 * 32
so its 29.49?
but wats the unit for it tho?
It'll be g/mol. Remember, the rates cancelled out when you did the division. Then, when you multiplied by 32 g/mol, the g/mol went with it. It also makes sense that we're solving the molar mass of Mb, it should be in g/mol.
so is 29.49 g/mol the final anwser?
But yes, 29.49 g/mol is the correct molar mass of the unknown gas. Use the Periodic Table and the list of gases given to figure out which one matches.
The question asks to identify which gas has that molar mass.
ok is it sodium?
It's not sodium, that's a metal. The question gives you about 6 different gases that can be the answer. You'll have to find the molar masses of all of them to find the right one.
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