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OpenStudy (anonymous):

The effusion rate of an unknown gas is measured and found to be 31.50 mL/min. Under identical experimental conditions, the effusion rate of O2 is found to be 30.50 mL/min. If the choices are CH4, CO, NO, CO2, and NO2, what is the identity of the unknown gas?

OpenStudy (anonymous):

OpenStudy (anonymous):

@iPwnBunnies @parna @primeralph

OpenStudy (anonymous):

its kinetic molecular theory

OpenStudy (anonymous):

@RatzLover95

OpenStudy (ipwnbunnies):

Use Graham's Law of Effusion.

OpenStudy (anonymous):

BUT HOW i never used this law

OpenStudy (ipwnbunnies):

\[\frac{rate_a}{rate_b} = \sqrt{\frac{M_b}{M_a}}\]

OpenStudy (anonymous):

im confused ?

OpenStudy (ipwnbunnies):

The ratio of the two rates of two gases is equal to the square root of molar masses of the two gases, but flipped

OpenStudy (anonymous):

i stil dont get it

OpenStudy (ipwnbunnies):

We know the rate of effusion for the O2 and the unknown gas. We know the molar mass of O2 from the Periodic Table. We just need to find M of the unknown gas.

OpenStudy (anonymous):

wait so 30.50 ml is ma?

OpenStudy (ipwnbunnies):

No, that is the rate of one of the O2.

OpenStudy (ipwnbunnies):

Let A be the O2, and B be the unknown gas. We're trying to find Mb.

OpenStudy (anonymous):

ok and wats ma?

OpenStudy (ipwnbunnies):

Ma is the molar mass of O2.

OpenStudy (anonymous):

31.50ml/min is ma?

OpenStudy (ipwnbunnies):

No..That's the rate of the unknown gas, B.

OpenStudy (ipwnbunnies):

Let's solve for Mb first, that's what we're trying to find so we can identify the unknown gas.

OpenStudy (anonymous):

is this right so far 30.50ml/min/31.50ml/min?

OpenStudy (ipwnbunnies):

Yeah, that'll be the left side. Next step to isolate Mb?

OpenStudy (anonymous):

how do you find ma though?

OpenStudy (ipwnbunnies):

We can find Ma from the Periodic Table. O2 has two moles of oxygen in it. From the Periodic Table, we can see O has a molar mass of 16 g/mol. So, O2 has a molar mass of 32 g/mol

OpenStudy (anonymous):

oh ok so its 30.50ml/min/31.50ml/min=square root of mb/32g/mol?

OpenStudy (ipwnbunnies):

Yes.

OpenStudy (anonymous):

ok so the left anwser is .96ml/min?

OpenStudy (ipwnbunnies):

Sure, I trust you can do that lol.

OpenStudy (anonymous):

is it right?

OpenStudy (ipwnbunnies):

Just that part? Idk...I'm pretty sure it should be that. Now, next step in solving for Mb?

OpenStudy (anonymous):

so for the square root dont you multiply by ^2 to cancel the square root symbol?

OpenStudy (ipwnbunnies):

That's not multiplying. But you do square both sides to get rid of that square root.

OpenStudy (anonymous):

oh i meant square sorry

OpenStudy (anonymous):

so is the left 0.96ml/min^2?

OpenStudy (ipwnbunnies):

Well, yeah. But you have to square the number for it to be useful. :3

OpenStudy (anonymous):

so i square 32 as well?

OpenStudy (ipwnbunnies):

Plus, there are no units, since when you divided those two rates, the units cancelled out.

OpenStudy (anonymous):

@RatzLover95

OpenStudy (ipwnbunnies):

No, when you square the right side, you just get rid of the square root there. The numbers don't change.

OpenStudy (anonymous):

oh ok then wat?

OpenStudy (anonymous):

then do u multpily 32 nd .96?

OpenStudy (ipwnbunnies):

Well, what number did you get on the left side? You had to square 0.96.

OpenStudy (anonymous):

yes?

OpenStudy (ipwnbunnies):

o.o Square 0.96, since we squared both sides.

OpenStudy (anonymous):

so u multpily square .96 and 32?

OpenStudy (ipwnbunnies):

Err, ok, yeah, we can keep the square there for now. Yes, now you'll have to multiply by 32 to get Mb by itself.

OpenStudy (anonymous):

kay well i got 30.72?

OpenStudy (ipwnbunnies):

You didn't square the 0.96 like I told you to.

OpenStudy (ipwnbunnies):

(0.96)^2 * 32

OpenStudy (anonymous):

so its 29.49?

OpenStudy (anonymous):

but wats the unit for it tho?

OpenStudy (ipwnbunnies):

It'll be g/mol. Remember, the rates cancelled out when you did the division. Then, when you multiplied by 32 g/mol, the g/mol went with it. It also makes sense that we're solving the molar mass of Mb, it should be in g/mol.

OpenStudy (anonymous):

so is 29.49 g/mol the final anwser?

OpenStudy (ipwnbunnies):

But yes, 29.49 g/mol is the correct molar mass of the unknown gas. Use the Periodic Table and the list of gases given to figure out which one matches.

OpenStudy (ipwnbunnies):

The question asks to identify which gas has that molar mass.

OpenStudy (anonymous):

ok is it sodium?

OpenStudy (ipwnbunnies):

It's not sodium, that's a metal. The question gives you about 6 different gases that can be the answer. You'll have to find the molar masses of all of them to find the right one.

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