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Mathematics 8 Online
OpenStudy (anonymous):

Imagine you are moving into a new room. You want to put in new carpeting, wallpaper and a wallpaper border that will go around the top of the wall. Take the dimensions of your room (length, width and height), and find how much carpeting, wallpaper and decorative borders are needed.

OpenStudy (shadowlegendx):

So this is something that you have to do with your room I'm guessing?

OpenStudy (anonymous):

My teacher said I need to make up the rooms dimensions.. that's why it says "imagine"

OpenStudy (shadowlegendx):

Ok so make up the dimensions

OpenStudy (anonymous):

make it 12 feet wide, 18 feet long, and 10 feet tall

OpenStudy (anonymous):

there u go

OpenStudy (anonymous):

Yeah so just bs this assignment! Treat it like a english course!

OpenStudy (anonymous):

Okay so I would need 316 ft of carpeting because area=lw..Is this right?

Miracrown (miracrown):

yes correct.

OpenStudy (anonymous):

And for the wallpaper & border is it 2l*2w?

Miracrown (miracrown):

the wallpaper and the border are separated

OpenStudy (anonymous):

wait 2l+2w for the border

Miracrown (miracrown):

think of the border as the blue ribbon going around the top section of the room

Miracrown (miracrown):

that is its total length, yes multiply that by its width to get its area

OpenStudy (anonymous):

Sooo...I imagined my new rooms dimensions are 12 feet wide, 18 feet long, and 10 feet tall. I would need 316 ft of carpeting. For the decrotive borderes I would need 60 ft. Last, I would use 720 ft of wallpaper..... Is that all right?

Miracrown (miracrown):

That is not exactly correct just as you did for the carpeting, you need to find the area of each not the perimeter notice how you found the area for teh carpeting. To find the area of the decorative border , you need not only the perimeter, but also its width, how wide do you want to draw it?

OpenStudy (anonymous):

Im confused cause she noted (Remember: Area of a rectangle is length times width. For the border you will use the perimeter of a rectangle, two times length plus two times width.)

Miracrown (miracrown):

right, with that you find the total perimeter multiply that by the border's width, which can be anything from 0.01 feet to 9.99 feet I would use 0.1 feet for instance

OpenStudy (anonymous):

Oh okay I get what you're saying now I think. So basically for the border I would do 2(18)+2(12)*0.1?

OpenStudy (kainui):

Imagine your room fits in a grain of sand, and the dimensions are on the order of being a quantum dot. This removes the necessity of having a door, so it makes calculations easier since you can just tunnel in and out.

OpenStudy (anonymous):

now im super confused

OpenStudy (anonymous):

^ this

OpenStudy (anonymous):

what kai said

OpenStudy (anonymous):

you have to do length times with times hight

Miracrown (miracrown):

yes, like this: (2(18)+2(12))*0.1 when you type it, you need to use an extra parenthesis

Miracrown (miracrown):

the perimeter must be first calculated, then multiply the result by 0.1

Miracrown (miracrown):

using the parenthesis forces us to first calculate the perimeter do you see what I mean?

OpenStudy (anonymous):

Okay yes I see what you're talking about..

Miracrown (miracrown):

^^ ;)

Miracrown (miracrown):

what did you get for the area of the border?

OpenStudy (anonymous):

6 ft

OpenStudy (anonymous):

Now what about for the wallpaper?

OpenStudy (anonymous):

@Kainui Wouldn't it make the calculations a tad bit tougher, probably have to deal with some nasty numbers such as 2.42*10^-20 m ew. But, then again a door wouldn't exist, unless you're a quantum organism, wow that would be something? I don't think we're smart enough to even imagine that? Oh another, thing at the quantum level, actually you're right you wouldn't need doors, because you'd be teleporting, yes at this stage you have to use science fiction words.

Miracrown (miracrown):

yes perfect megan ;)

OpenStudy (anonymous):

thanks by the way for all your help!

Miracrown (miracrown):

You're quite welcome... ^^ :-]

Miracrown (miracrown):

one more thing - what will the area of the wallpaper be?

OpenStudy (anonymous):

ummmm... lol

Miracrown (miracrown):

just like we found the area of the border, we find the area of the wallpaper you might as well consider it a border , but a lot wider...

OpenStudy (anonymous):

this is longest thread ever

Miracrown (miracrown):

mesh <3333

OpenStudy (anonymous):

hii

OpenStudy (anonymous):

Okay so its still 2l+2w multiplied by the wallpapers width?

Miracrown (miracrown):

u figured how to change ur pic ?

Miracrown (miracrown):

and exactly megan!

OpenStudy (anonymous):

i had problems beause i am drinking

Miracrown (miracrown):

so the question is , what is its width? :)

Miracrown (miracrown):

O.O --- drinking? Since when?

OpenStudy (anonymous):

6 this morning

OpenStudy (anonymous):

Wow you must be really MESHed up...see what I did there?

Miracrown (miracrown):

lol man

OpenStudy (anonymous):

@Megan_xoxo Sorry for taking your thread off topic, did you get the solution you were looking for?

Miracrown (miracrown):

if the total height of your room is 10 and the width of the border is 0.1, what is left for the height of the wallpaper? @Megan_xoxo

OpenStudy (anonymous):

594 ft for the wallpaper.

OpenStudy (anonymous):

and it's totally okay I don't mind lol!

Miracrown (miracrown):

Yes, rigth! oh ha ha ha, lol

OpenStudy (anonymous):

Should've wrote na na na, instead of ha ha ha, then I could've said batman!

OpenStudy (anonymous):

I imagined my new rooms dimensions are 12 feet wide, 18 feet long, and 10 feet tall. I would need 316 ft of carpeting because 12*18=316. For the decorative borders I would need 6 ft because (2(18)+2(12))*0.1=6 . Last, I would use 594 ft of wallpaper because (2(18)+2(12))*9.9=594.

OpenStudy (anonymous):

Now is it all correct? Lol

OpenStudy (anonymous):

Looks correctomento to me!

Miracrown (miracrown):

Brilliant! that is precisely right... ;)

OpenStudy (anonymous):

K thanks :)

OpenStudy (anonymous):

++++ clap clap :D

Miracrown (miracrown):

no worries

Miracrown (miracrown):

awww, mesh - aren't you just sweet?

OpenStudy (anonymous):

loll

OpenStudy (anonymous):

you r sweeter

OpenStudy (anonymous):

\[\huge {MEGANXOXO YOU DID GOOD!}\]

OpenStudy (anonymous):

than me :P

OpenStudy (anonymous):

\[\huge BATMAN\]

OpenStudy (anonymous):

lol ♥ @iambatman

Miracrown (miracrown):

no corrections you're... cause u've got sweet fruits! :-] nd I don't unfortunatly! :{

OpenStudy (anonymous):

\[\huge \int\limits_{0}^{1} lnx dx\] Now do this problem, any takers?

Miracrown (miracrown):

Do you guys think of me as a machine or what? O.O

OpenStudy (anonymous):

\[\Huge \int\limits udv = uv-\int\limits vdu\] Use that @Miracrown

OpenStudy (anonymous):

@Kainui

OpenStudy (kainui):

integral of lnx whats that, looks like letters to me.

OpenStudy (anonymous):

\[\huge CORRECT\]

OpenStudy (anonymous):

|dw:1398680373655:dw|

OpenStudy (anonymous):

You literally spent like 9 hours typing, and a empty drawing shows up -.-

OpenStudy (anonymous):

|dw:1398680573784:dw||dw:1398680887134:dw|

Miracrown (miracrown):

Mesh this is just a waste of time since its useless.

OpenStudy (anonymous):

It's not wirjinf

Miracrown (miracrown):

Kill it >< !

OpenStudy (anonymous):

Bye :o

Miracrown (miracrown):

Go for it

Miracrown (miracrown):

-_-

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