Question

x^2 + 9 < (x+3)^2 < 8x + 25

The number of the integral sollutions of this equation is.

Answer 1

(0 , infinty) and x(x-2)-16<0

Answer 2

Hey, sorry I'm going to bed right now, but try @Kainui he can probably help you with your problem :P

Answer 3

OK

Answer 4

I did 90% of it

Answer 5

(0 , infinty) and x(x-2)-16<0

Answer 6

1√17<x<1+√17

Answer 7

I didn't get you

Answer 8

@ParthKohli

Answer 9

@paki

Answer 10

@hartnn

Answer 11

Hi.

Answer 12

Hello

Answer 13

(0 , infinty) and x(x-2)-16<0

Answer 14

First, solve\[x^2 + 9 < (x + 3)^2\]Then, solve\[(x + 3)^2 < 8x + 25\]You'll get two intervals. You have to satisfy both intervals, so take the common part - or the intersection.

Answer 15

(0 , infinty) and x(x-2)-16<0

Answer 16

What will be the critical points for x(x-2)-16<0

Answer 17

Expand that and you'll get a quadratic equation

Answer 18

we cant solve it its discriminant is not a perfect square

Answer 19

I meant factorise

Answer 20

\[x^2 + 6x + 9 < 8x + 25\]\[x^2 - 2x - 16 < 0\]If the discriminant is not a perfect square, then use the quadratic formula to get the critical points.

Answer 21

Basically, the roots are the critical points, right?

Answer 22

ok wait a min