Please help!! If the cos of angle x is 8 over 17, and the triangle was dilated to be two times as big as the original, what would be the value of the cos of x for the dilated triangle? Hint: Use the slash symbol ( / ) to represent the fraction bar and enter the fraction with no spaces.
assume its a right triangle
after dilation, the sides will be 2 times longer : ` 2*8x`, `2*17x`
take the cos ratio again : cos = \(\dfrac{2*8x}{2*17x} = \dfrac{\not 2*8\not x}{\not2*17 \not x} = \dfrac{8}{17}\)
So, the ratio didnt change. looks the cos ratio is not affected by dilation ?
it's supposed to be in fraction, so should I just put not effected?
Nope.
just put the old fraction
ah! Ok! Thank you very much!
just put \(\dfrac{8}{17}\) okay ?
np.. u wlc :)
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