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Mathematics 18 Online
OpenStudy (anonymous):

Solve the inequality 2x - 3 < x + 2 ≤ 3x + 5. Show your work.

OpenStudy (anonymous):

break it into two.

OpenStudy (anonymous):

2x - 3 < x+2 x + 2 ≤ 3x + 5

OpenStudy (anonymous):

2x - 3 < x+2 x < 5 then x + 2 ≤ 3x + 5 - 2x ≤ 3 -3/2 ≤ x put it back together now -3/2 ≤ x < 5

OpenStudy (anonymous):

thats it?

OpenStudy (anonymous):

Do you understand?

OpenStudy (anonymous):

not really lol

OpenStudy (anonymous):

ok stay with me

OpenStudy (anonymous):

2x - 3 < x + 2 ≤ 3x + 5 We are working each part separately So there is 2x - 3 < x + 2 and x + 2 ≤ 3x + 5 do you get this part?

OpenStudy (anonymous):

it is just like saying A = B = C so it is still right to say A =B and B =C

OpenStudy (anonymous):

ooh so you solve each part separetely and then you put the answer together?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

oooh which sign do I use to put them together?

OpenStudy (anonymous):

the one that is originally there

OpenStudy (anonymous):

first 2x - 3 < x+2 x < 5 then x + 2 ≤ 3x + 5 - 2x ≤ 3 -3/2 ≤ x put it back together now -3/2 ≤ x < 5

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