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Chemistry 17 Online
OpenStudy (xmoses1):

I hate asking questions in Chem because nobody ever answer them. But here it goes anyway: Equilibrium is established in a reversible reaction when? the [product] = [reactants] the rate of reaction of the products = the rate of reaction of the reactants all the reactants dissolve or dissociate when products are no longer produced

OpenStudy (xmoses1):

@e.mccormick Chem help :D

OpenStudy (xmoses1):

@thomaster ?

OpenStudy (xmoses1):

B?

OpenStudy (anonymous):

the rate of reaction of the products = the rate of reaction of the reactants

OpenStudy (hitaro9):

Yes, it would be B. You can think of equilibrium like a library loaning out books. If the number of people taking out a book each day is equal to the number of people returning them, then there's no issue, as when a person comes in to pick up a book someone will be returning it, and everyone's happy. It's not A, as if it starts out at say, 5 books in and 5 books out, but then 1000 people all come in wanting those books, it very soon becomes unequal. D Isn't right, as if books aren't being loaned out, then there's no equilibrium established. C isn't really even relevant.

OpenStudy (anonymous):

When the ratio of concentrations of the reactants and products is stable. so its the first one the [product] = [reactants]

OpenStudy (accessdenied):

The concentrations of the reactants and products need not be equal. Either side could be heavily favored, and this is why we have equilibrium constants -- not all equilibrium constants are equal to 1 ([products] = [reactants]). The only condition is that reactants are being produced just as quickly as products, because the net change in each concentration becomes 0.

OpenStudy (xmoses1):

Wow thanks everyone!

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