Question

@phi

Answer 1

im not sure about 6, and 2

Answer 2

I don't see a 6, but 5 looks like it converges absolutely

Answer 3

sorry, i mean to say 5, typo :)

Answer 4

2 looks like it converges absolutely

i.e. 1/sqr(n) -> 0

Answer 5

for 5, if you replace sin(3n) with its max value you have 1/n^2
which converges
that means if we replace sin(3n) with |sin(3n)| it will converge (#'s will be ≤ 1 )
so converge absolutely

Answer 6

3) looks dubious

Answer 7

what about 1, is that one okay?
i wan't sure if 10^2-1 would become 10^2+1 after the use of the absolute value when i was doing the problem

Answer 8

10^2 -1 is just a way to write 99

Answer 9

so for 1) every term is always positive.

Answer 10

Thanks, i got it, i have one more left, can you help me with it?

Answer 11

Did you post it ?

Answer 12

not yet