Find the derivative of f(x) = 5 divided by x at x = -1.
use the power rule, keep in mind that \(\bf f(x)=\cfrac{5}{x}\implies f(x)=5x^{-1}\)
okay can u show me how to go from there, 5x^-1 is probably easier to use in the power rule formula right?
yes... the other way would be using the product formula, which will be a bit longer, is all
rather the "quotient" formula
\(\bf f(x)=\cfrac{5}{x}\implies f(x)=5x^{{\color{red}{ -1}}}\implies f(x)={\color{red}{ -1}}\cdot 5\cdot x^{{\color{red}{ -1}}-1}\)
that'd give you the derivative equation, then just plug in "-1" for its "x" argument
okay so would the derivative be -5?
no
what is -1-1
-2
that is your exponent on x
okay so x^-2 or 1/x^2 right?
\(\bf f(x)=\cfrac{5}{x}\implies f(x)=5x^{{\color{red}{ -1}}}\implies f(x)={\color{red}{ -1}}\cdot 5\cdot x^{{\color{red}{ -1}}-1} \\ \quad \\ f'(x)=-5x^{-2}\qquad \textit{when x = -1, thus}\quad f'({\color{blue}{ -1}})=-5({\color{blue}{ -1}})^{-2}\)
ohhhhhh okayy so i would simplify then plug in the x=-1 in for x in the new equation
yeap
okay so the derivative is -5 right?
yeap
the derivative isnt -5. but at f(-1)=-5
f'(-1)
right
ohhhhhh okayyyy thank youuu so muchhh, really helpfull
yw
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