A student studying for a vocabulary test knows the meanings of 16 words from a list of 20 words. If the test contains 10 words from the study list, what is the probability that at least 8 of the words on the test are words that the student knows? (Round your answer to three decimal places.)
You need to find the separate probabilities that 8, 9 and 10 of the words on the test are words that the student knows. Next these 3 values of probability are added to find the probability that at least 8 of the words on the test are words that the student knows. Do you want me to help you through the work?
please?
\[P(8\ words\ known)=\frac{{16 \choose 8}{4 \choose 2}}{{20 \choose 10}}\] Can you calculate the above step?
yes, thank you
Can you please post your result. Then we can move on to the next step.
That answer equals 2, and i thought probability had to be between 0 and 1
I get a result for P(8 words known) that is less than 1. Can we go thru your calculation?
what I got is 2*2/2 or 4/2 = 2
Are you familiar with combinations and permutations. In the calculation for P(8 words known) \[{16 \choose 8}\] means 16 choose 8. Do you know how to calculate this combination?
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