Construct a polynomial function with the following properties: fifth degree, 4 is a zero of multiplicity 2, -3 is the only other zero, leading coefficient is 4.
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OpenStudy (anonymous):
do you know what "multiplicity" means in this context?
OpenStudy (anonymous):
Not really
OpenStudy (anonymous):
if \(a\) is a zero of \(p(x)\) of multiplicity \(n\) then \(p(x)\) has a factor of \((x-a)^n\)
OpenStudy (anonymous):
for example, if \(4\) is a zero of multiplicity 2, then the polynomial has a factor of \((x-4)^2\) to bring it more down to earth (and also answer your question)
OpenStudy (anonymous):
at least partially answer it
since the other zero is \(-3\) there is a factor of \((x+3)\)
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OpenStudy (anonymous):
So do I multiply (x+3)(x-2)^2 and then 4 in order to get 4x^5?
OpenStudy (helder_edwin):
u r close. it should be
\[\large f(x)=4\cdot(x+3)^n(x-4)^2 \]
in order to get a polynomial of degree 5, what should be the value of n?
OpenStudy (anonymous):
3
OpenStudy (anonymous):
Correct?
OpenStudy (helder_edwin):
yes
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