Please help!! Test on this tomorrow! If f varies directly as g and inversely as the square of h, and f=20 when g=50 and h=5, find f when g=18 and h=6. I totally understand what direct and inverse mean and how to set up the problem. I just don't know what to do whenever it's varied to something SQUARED. Do I square the number given? I really need to see what's done step by step and then I'll be confident I'm getting the other ones like this correct. Thanks!
@satellite73 @geekfromthefutur @paki @sourwing @agent0smith
My teacher explained the y=kx and the y=k/x and all that, just not what to do when it's squared. Never seen anything similar in my book so I want to make sure I'm on the right track
what you want to ask...?
How do I solve a problem like this? I understand to PLUG IN the numbers to their proper places, but (for instance) should I SQUARE h? And If I do square h, when I find k and plug it back in, should I square the new h value again?
hmmm... ok... for squaring the number.... just put square over them and solve... other steps are similar like solving the direct and indirect proportions....
So I set up, f=gk/h 20=(5^2)k/50 so k = 100 plug back in now f=18(100)/6 f=300 correct answer?
look, what is the value of g and h... check it in youir formula...
g=50 and h=5 in the first, then g=18 and h=6
My bad, I didn't square the second time. 6 squared is 36. so it would be f = 50
so how you put the values in,,, f=gk/h
hmmm :-)
Simple fact error lol my fault. Thank you for your help though I understand it a lot better now! so f=50 is the correct answer!
yeah ;-) and pleasure
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