Question

The following problem involves some factoring by grouping. Remember, before you can divide out factors common to the numerators and denominators of a product, you must factor completely.

Answer 1

\[\frac{ x^3-3x^2+4x-12 }{ x^4-16 } * \frac{ 24x^2+40x-16 }{ 3x^2-10x+3 }\]

Answer 2

the denominator is 4(6x^2+10x-4)

Answer 3

the second numerator *

Answer 4

i think

Answer 5

you are correct, but can you further factor whatever is inside the parenthesis?

Answer 6

4(3x+2)(2x+2)

Answer 7

x^4-16 is (x^2+4)(x^2-4)?