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Mathematics 26 Online
OpenStudy (anonymous):

If f(x) = 2x and g(x) = 5x, calculate f(g(x)). @cgreenwade2000

OpenStudy (cgreenwade2000):

This one is a little different. Instead of multiplying the two together here, you want to substitute the entire expression of g into f.

OpenStudy (anonymous):

so 2x * 5x*2x ?

OpenStudy (cgreenwade2000):

For example: f(x) = 25x g(x) = 4x^2 so f(g(x)) = 25(4x^2) everywhere here there was an x I substituted it out with g(x)

OpenStudy (cgreenwade2000):

Not quite.

OpenStudy (anonymous):

oh, so 2x(5x)

OpenStudy (cgreenwade2000):

Anywhere you see and x in f(x), you are going to take it out and put the entire expression of G(x) instead

OpenStudy (anonymous):

wouldnt it still be 10x^2

OpenStudy (cgreenwade2000):

No, try again

OpenStudy (anonymous):

so ((2x)*5x *5x)

OpenStudy (cgreenwade2000):

Anywhere you see and x in f(x), you are going to take it out and put the entire expression of G(x) instead

OpenStudy (anonymous):

i tried

OpenStudy (cgreenwade2000):

What does f(x) equal?

OpenStudy (anonymous):

2x

OpenStudy (cgreenwade2000):

Anywhere you see an x in f(x), you are going to take it out and put the entire expression of G(x) instead

OpenStudy (cgreenwade2000):

Take out the x in f(x) and put in what g(x) is equal to there.

OpenStudy (cgreenwade2000):

It should look like this 2(whatever g(x) is)

OpenStudy (anonymous):

so (2)(5x)

OpenStudy (cgreenwade2000):

Yeah, thats it. Now you simplify that and you have f(g(x)) Similarly g(f(x)) is just putting in f(x) for every x in g

OpenStudy (anonymous):

either way it still 10x

OpenStudy (cgreenwade2000):

Yep. It won't always be like that, but in this case it is.

OpenStudy (anonymous):

thank you,

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