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The ages of students in a school are normally distributed with a mean of 15 years and a standard deviation of 2 years. Approximately what percent of the students are between 14 and 18 years old?
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24.17% 62.47% 30.85% 93.32%
\[P(14<x \le18)=P(\frac{ 14-15 }{ 2 }<z \le \frac{ 18-15 }{ 2 })\]
How do I find the percent of the students from here?
\[P(-0.5<z \le1.5)=P(z \le 1.5)-[1-P(z \le 0.5)]\]
tell me what number you find in the table for 1.5
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0.4332? OK, what do I do now w. this number?
sorry man in this table: http://4.bp.blogspot.com/_5u1UHojRiJk/TEh9BHxxPUI/AAAAAAAAAIQ/DafeQNMYFoE/s1600/ztable.gif
@lopus ?
this number is z<1.5 later do z<0.5 and replace it in equation
tell me you can solve it
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