Question

.

Answer 1

@Loser66

Answer 2

ok, for part A) the horizontal tangent line of the graph is at x = -2 and x= 3. that 's the answer for A

Answer 3

f(x) concave up when f"(x)>0, concave down whenf"(x) <0 so that [-2.6,-2] and [1,3] are the intervals where f"(x) <0 , concave down
[-2,1] and [3,3.6] , f"(x) >0 , concave up. That's for B

Answer 4

for c) we know that at x = -0.9 the graph is concave up, so that it should be a local min
at x = 1.37 , the graph is concave down, so that it should be a local max (if they are critical points)

Answer 5

Dat's all I know

Answer 6

You are duh bestttt :D Will you help me with another problem? It's similar to this one and I will make a new post for u

Answer 7

hey, if it is similar, why don't you do it by yourself, just imitate the steps