Ask your own question, for FREE!
Chemistry 21 Online
OpenStudy (anonymous):

I just learned how to do limited reactions, but still need a little help.. 1. Phosphorus(s) reacts with fluorine(g) to yield diphosphorus tetrafluoride(g). Determine how many grams of diphosphorus tetrafluoride(g) will be produced by the reaction 9415 decigrams of phosphorus(s) with excess fluorine. Thank you

OpenStudy (anonymous):

I would love to help you but I haven't yet learned that :(

OpenStudy (anonymous):

thanks anyway

OpenStudy (anonymous):

So sorry! Thank you again, best of luck!

OpenStudy (anonymous):

np

OpenStudy (anonymous):

@alpha_omega32

OpenStudy (anonymous):

@Alpha_Omega32

OpenStudy (anonymous):

@Ahlpa_Omega32

OpenStudy (anonymous):

Okay, hold on, lemme try and figure it out.

OpenStudy (anonymous):

ok..i know the first step is to write the balanced equation: 2P+4F yields P2F4

OpenStudy (anonymous):

Right

OpenStudy (anonymous):

Do you have any idea what the next step would be?

OpenStudy (anonymous):

|dw:1398817640693:dw|

OpenStudy (anonymous):

this is guess

OpenStudy (anonymous):

I'm not so sure myself, I'm trying to understand it.

OpenStudy (anonymous):

its limited reactions...but there aren't two givens so im confused

OpenStudy (anonymous):

Yeah, I'm a little confused myself.

OpenStudy (anonymous):

well its alright, thanks anyway

OpenStudy (anonymous):

Yeah, no problem.

OpenStudy (anonymous):

I think I can get my brother to help you.

OpenStudy (anonymous):

@Anonymous_101_

OpenStudy (anonymous):

So, it looks like my sister wanted me to help you, so thats what I'll do.

OpenStudy (anonymous):

oh well thanks :)

OpenStudy (anonymous):

I'm sorry but I have to leave, if I could I would stay and help, I'm apologies.

OpenStudy (anonymous):

oh its alright but thanks

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!