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Mathematics 22 Online
OpenStudy (anonymous):

Factor the following by grouping. y^2+5x+5y+xy

OpenStudy (anonymous):

So to factor by grouping you find something that can be a common factor between the two. Looking at the equation, it will involve y and 5. If we group like-looking factors (has x, has only y), we get:\[y ^{2}+5y+xy+5x\] factoring things out, we can get:\[y(y+5)+x(y+5)\] which simplifies into:\[(y+x)(y+5)\] Any grouping question is simply looking for like factors that can be pulled out of different parts. If this can be done, then the equation should be easily factorable.

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