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double integral
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polar coordinates, \[-x^2-y^2+z^2=1 \] and the plane z=2
convert to polar coordinates to find the volume
@ganeshie8
u know jacobians?
no
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|dw:1398952691753:dw|
lets sketch the both surfaces and get a feel how the volume between them looks
\(-x^2-y^2+z^2=1 \) \(z^2=1+x^2+y^2 \implies z = \pm \sqrt{1+x^2+y^2}\) is a two sheeted hyperboloid , but we only need the upper part
|dw:1398952879366:dw|
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