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how to take the derivative of the sum of an equation? i will award a medal if you help me get the right answer!
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y is a function y = y(x). C = constant, the derivative(y') of a constant is 0. The formula for the derivative is: y= x^n = > y' = nx^n-1
\[d/dx \sum_{o}^{\inf} [(x^(2n)))/n!]\]
x is raised to the power 2n
\[d/dx \sum_{n=o}^{\inf} [(x^(2n)))/n!]\]
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