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Mathematics 7 Online
OpenStudy (anonymous):

Candle P and candle Q of equal length are lighted at the same time and burning until candle P is twice as long as candle Q. Candle P is designed to fully burn in 8 hours while candle Q for 4 hours. How long will they be lighted?

OpenStudy (anonymous):

I got 8/3 hours Did you try with something?

OpenStudy (anonymous):

How?

OpenStudy (anonymous):

First of all for all written question you need to write equations first. However for equations you need to decide the variables. What should be the variables of this problem?

OpenStudy (anonymous):

Was that a rate problem?

OpenStudy (anonymous):

No

OpenStudy (anonymous):

Can you try to answer my question? What are the unknowns?

OpenStudy (anonymous):

Length of the candles and the required is the time it would take them to be finished. Is there any tricky part in the question?

OpenStudy (anonymous):

Not so tricky. And yes those are what we need sort of.

OpenStudy (anonymous):

Let us translate English to Maths now

OpenStudy (anonymous):

In order to do so we need to label clearly the unknowns. Let t be the time needed to reach the given state. Let l be the length of the candles at the start. Let x be the length of candle P at any given time t. Let y be the length of candle Q at any time t.

OpenStudy (anonymous):

Now we know that at time t one candle is double the length than the other. Thus x=2y

OpenStudy (anonymous):

We need a formula for x and y now. This is the tricky part I assume

OpenStudy (anonymous):

\[x=l-t \frac{ l }{ 8 }\]

OpenStudy (anonymous):

\[y=l-t \frac{ l }{ 4 }\]

OpenStudy (anonymous):

If you solve this system of equations. You will get your answer.

OpenStudy (anonymous):

This is the method I use when facing written maths problems. I hope it helped.

OpenStudy (anonymous):

So basically, the equation is based on lengths, not time? I see!.. Thanks, Merci!

OpenStudy (anonymous):

It helped a lot!

OpenStudy (anonymous):

When you solve it l will drop out and you will get to t=something

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